THE FORMULA FOR GRAVITY BY MR TERRY GARDNER BORN 19th FEBRUARY 1970:
DATED 26th JANUARY 2020.
THE GRAVITATIONAL FORMULA IS:
a= The amount of celestial bodies in orbit with each other.
b=Radius of the celestial body. This is measured in 1000km...For example earth which is 6,371 km would be 6.371 1000 km.
Gravity (g)=b2+-b-4a divided by 3 +- a factor of 3 ( or not at all )
divided by 100 Multiplied by 100 +- 3% or a Factor of 3% divided or multiplied by a Power of 10.
THE MATHEMATICAL PROOF IS:
a=gravity. b=radius c=amount of celestial bodies
number=b+-b2-4ac divided by 3+- a factor of 3.
The gravitational constant in 3 dimensional space is 27651.23. The gravitational constant in 1 direction is 23285.25 which is the value of 1/8th the speed of light at 186,282 miles per second.
You divide the radius ( IN M NOT 1000 KM) by the 3d gravitational constant ( 27651.23 ) and the by the derived number divided by 100 multiplied by 100 +- 3% or a factor of 3% divided or multiplied by a power of 10.
The formula is an approximation but is safe because all gravity's by celestial bodies in the solar system if not the universe are inter related. It also proves that celestial bodies in orbit with each other ( & therefore matter ) cancels out part of each Gravitational fields.
That is all & God save Queen Elizabeth the II
THE GRAVITATIONAL FORMULA IS:
a= The amount of celestial bodies in orbit with each other.
b=Radius of the celestial body. This is measured in 1000km...For example earth which is 6,371 km would be 6.371 1000 km.
Gravity (g)=b2+-b-4a divided by 3 +- a factor of 3 ( or not at all )
divided by 100 Multiplied by 100 +- 3% or a Factor of 3% divided or multiplied by a Power of 10.
THE MATHEMATICAL PROOF IS:
a=gravity. b=radius c=amount of celestial bodies
number=b+-b2-4ac divided by 3+- a factor of 3.
The gravitational constant in 3 dimensional space is 27651.23. The gravitational constant in 1 direction is 23285.25 which is the value of 1/8th the speed of light at 186,282 miles per second.
You divide the radius ( IN M NOT 1000 KM) by the 3d gravitational constant ( 27651.23 ) and the by the derived number divided by 100 multiplied by 100 +- 3% or a factor of 3% divided or multiplied by a power of 10.
The formula is an approximation but is safe because all gravity's by celestial bodies in the solar system if not the universe are inter related. It also proves that celestial bodies in orbit with each other ( & therefore matter ) cancels out part of each Gravitational fields.
That is all & God save Queen Elizabeth the II
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